3^2+3y^2=3

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Solution for 3^2+3y^2=3 equation: 



3^2+3y^2=3

We move all terms to the left:

3^2+3y^2-(3)=0

determiningTheFunctionDomain
3y^2-3+3^2=0

We add all the numbers together, and all the variables

3y^2+6=0

a = 3; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·3·6
Δ = -72
Delta is less than zero, so there is no solution for the equation

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